4[2+x(x-3)]=8

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Solution for 4[2+x(x-3)]=8 equation:


Simplifying
4[2 + x(x + -3)] = 8

Reorder the terms:
4[2 + x(-3 + x)] = 8
4[2 + (-3 * x + x * x)] = 8
4[2 + (-3x + x2)] = 8
[2 * 4 + -3x * 4 + x2 * 4] = 8
[8 + -12x + 4x2] = 8

Add '-8' to each side of the equation.
8 + -12x + -8 + 4x2 = 8 + -8

Reorder the terms:
8 + -8 + -12x + 4x2 = 8 + -8

Combine like terms: 8 + -8 = 0
0 + -12x + 4x2 = 8 + -8
-12x + 4x2 = 8 + -8

Combine like terms: 8 + -8 = 0
-12x + 4x2 = 0

Solving
-12x + 4x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '4x'.
4x(-3 + x) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0

Subproblem 2

Set the factor '(-3 + x)' equal to zero and attempt to solve: Simplifying -3 + x = 0 Solving -3 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + x = 0 + 3 Combine like terms: -3 + 3 = 0 0 + x = 0 + 3 x = 0 + 3 Combine like terms: 0 + 3 = 3 x = 3 Simplifying x = 3

Solution

x = {0, 3}

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